(2/3b)+5=(20-b)

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Solution for (2/3b)+5=(20-b) equation: 



(2/3b)+5=(20-b)

We move all terms to the left:

(2/3b)+5-((20-b))=0



Domain of the equation: 3b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+2/3b)-((-1b+20))+5=0

We get rid of parentheses

2/3b-((-1b+20))+5=0

We multiply all the terms by the denominator


-(((-1b+20)))*3b+5*3b+2=0

Wy multiply elements

-(((-1b+20)))*3b+15b+2=0

We add all the numbers together, and all the variables

15b-(((-1b+20)))*3b+2=0

We move all terms containing b to the left, all other terms to the right

15b-(((-1b+20)))*3b=-2

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