(2/3b)+4=6

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Solution for (2/3b)+4=6 equation: 



(2/3b)+4=6

We move all terms to the left:

(2/3b)+4-(6)=0



Domain of the equation: 3b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+2/3b)+4-6=0

We add all the numbers together, and all the variables

(+2/3b)-2=0

We get rid of parentheses

2/3b-2=0

We multiply all the terms by the denominator


-2*3b+2=0

Wy multiply elements

-6b+2=0

We move all terms containing b to the left, all other terms to the right

-6b=-2

b=-2/-6

b=1/3

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