(2/3+4i)(3-i)=0

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Solution for (2/3+4i)(3-i)=0 equation:



(2/3+4i)(3-i)=0
Domain of the equation: 3+4i)(3-i)!=0
We move all terms containing i to the left, all other terms to the right
4i)(3-i)!=-3
i∈R
We add all the numbers together, and all the variables
(+4i+2/3)(-1i+3)=0
We multiply parentheses ..
(-4i^2+12i-2i^2+2/3*3)=0
We multiply all the terms by the denominator
(-4i^2+12i-2i^2+2=0

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