(2/3)z=7-(5/6)z

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Solution for (2/3)z=7-(5/6)z equation: 



(2/3)z=7-(5/6)z

We move all terms to the left:

(2/3)z-(7-(5/6)z)=0



Domain of the equation: 3)z!=0

z!=0/1

z!=0

z∈R





Domain of the equation: 6)z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+2/3)z-(7-(+5/6)z)=0

We multiply parentheses

2z^2-(7-(+5/6)z)=0

We multiply all the terms by the denominator


2z^2*6)z)-(7-(+5=0

Wy multiply elements

12z^3+5=0

We do not support ezpression: z^3

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