(2/3)x=4/8

Solution for (2/3)x=4/8 equation:

(2/3)x=4/8

We move all terms to the left:

(2/3)x-(4/8)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x-(+4/8)=0

We multiply parentheses

2x^2-(+4/8)=0

We get rid of parentheses

2x^2-4/8=0

We multiply all the terms by the denominator


2x^2*8-4=0

Wy multiply elements

16x^2-4=0

a = 16; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·16·(-4)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*16}=\frac{-16}{32}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*16}=\frac{16}{32}
=1/2
$