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(2/3)x-5x=x-16
We move all terms to the left:
(2/3)x-5x-(x-16)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x-5x-(x-16)=0
We add all the numbers together, and all the variables
-5x+(+2/3)x-(x-16)=0
We multiply parentheses
2x^2-5x-(x-16)=0
We get rid of parentheses
2x^2-5x-x+16=0
We add all the numbers together, and all the variables
2x^2-6x+16=0
a = 2; b = -6; c = +16;
Δ = b2-4ac
Δ = -62-4·2·16
Δ = -92
Delta is less than zero, so there is no solution for the equation
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