(2/3)x-4=2(x-3)

Solution for (2/3)x-4=2(x-3) equation:

(2/3)x-4=2(x-3)

We move all terms to the left:

(2/3)x-4-(2(x-3))=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x-(2(x-3))-4=0

We multiply parentheses

2x^2-(2(x-3))-4=0


We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)


We get rid of parentheses

2x^2-2x+6-4=0

We add all the numbers together, and all the variables

2x^2-2x+2=0

a = 2; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·2·2
Δ = -12
Delta is less than zero, so there is no solution for the equation