(2/3)x-10=32

Solution for (2/3)x-10=32 equation:

(2/3)x-10=32

We move all terms to the left:

(2/3)x-10-(32)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x-10-32=0

We add all the numbers together, and all the variables

(+2/3)x-42=0

We multiply parentheses

2x^2-42=0

a = 2; b = 0; c = -42;
Δ = b2-4ac
Δ = 02-4·2·(-42)
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{21}}{2*2}=\frac{0-4\sqrt{21}}{4}
=-\frac{4\sqrt{21}}{4}
=-\sqrt{21}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{21}}{2*2}=\frac{0+4\sqrt{21}}{4}
=\frac{4\sqrt{21}}{4}
=\sqrt{21}
$