(2/3)x-(1/6)=(1/2)

Solution for (2/3)x-(1/6)=(1/2) equation:

(2/3)x-(1/6)=(1/2)

We move all terms to the left:

(2/3)x-(1/6)-((1/2))=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x-(+1/6)-((+1/2))=0

We multiply parentheses

2x^2-(+1/6)-((+1/2))=0

We get rid of parentheses

2x^2-1/6-((+1/2))=0

We calculate fractions


2x^2+()/()+()/()=0

We add all the numbers together, and all the variables

2x^2+2=0

a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation