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(2/3)x+4=2/5
We move all terms to the left:
(2/3)x+4-(2/5)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x+4-(+2/5)=0
We multiply parentheses
2x^2+4-(+2/5)=0
We get rid of parentheses
2x^2+4-2/5=0
We multiply all the terms by the denominator
2x^2*5-2+4*5=0
We add all the numbers together, and all the variables
2x^2*5+18=0
Wy multiply elements
10x^2+18=0
a = 10; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·10·18
Δ = -720
Delta is less than zero, so there is no solution for the equation
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