(2/3)x+4=-6

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Solution for (2/3)x+4=-6 equation: 



(2/3)x+4=-6

We move all terms to the left:

(2/3)x+4-(-6)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x+4-(-6)=0

We add all the numbers together, and all the variables

(+2/3)x+10=0

We multiply parentheses

2x^2+10=0

a = 2; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·2·10
Δ = -80
Delta is less than zero, so there is no solution for the equation

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