(2/3)x+1=(1/3)x-6

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Solution for (2/3)x+1=(1/3)x-6 equation: 



(2/3)x+1=(1/3)x-6

We move all terms to the left:

(2/3)x+1-((1/3)x-6)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)x-6)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x-((+1/3)x-6)+1=0

We multiply parentheses

2x^2-((+1/3)x-6)+1=0

We multiply all the terms by the denominator


2x^2*3)x-6)-((+1*3)x-6)+1=0

We add all the numbers together, and all the variables

2x^2*3)x-6)-(3x-6)+1=0

Wy multiply elements

6x^3=0

We do not support expression: x^3

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