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(2/3)x+(5/6)x=(1/2)x+10
We move all terms to the left:
(2/3)x+(5/6)x-((1/2)x+10)=0
Domain of the equation: 3)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 6)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2)x+10)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3)x+(+5/6)x-((+1/2)x+10)=0
We multiply parentheses
2x^2+5x^2-((+1/2)x+10)=0
We multiply all the terms by the denominator
2x^2*2)x+10)+5x^2*2)x+10)-((+1=0
Wy multiply elements
8x^4=0
We do not support expression: x^4
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