(2/3)x+(4/3)=-(2/3)

Solution for (2/3)x+(4/3)=-(2/3) equation:

(2/3)x+(4/3)=-(2/3)

We move all terms to the left:

(2/3)x+(4/3)-(-(2/3))=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x+(+4/3)-(-(+2/3))=0

We multiply parentheses

2x^2+(+4/3)-(-(+2/3))=0

We get rid of parentheses

2x^2+4/3-(-(+2/3))=0

We calculate fractions


2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$