(2/3)v-(1/2)=-(1/5)

Solution for (2/3)v-(1/2)=-(1/5) equation:

(2/3)v-(1/2)=-(1/5)

We move all terms to the left:

(2/3)v-(1/2)-(-(1/5))=0


Domain of the equation: 3)v!=0

v!=0/1

v!=0

v∈R


We add all the numbers together, and all the variables

(+2/3)v-(+1/2)-(-(+1/5))=0

We multiply parentheses

2v^2-(+1/2)-(-(+1/5))=0

We get rid of parentheses

2v^2-1/2-(-(+1/5))=0

We calculate fractions


2v^2+()/()+()/()=0

We add all the numbers together, and all the variables

2v^2+2=0

a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation