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(2/3)t=-1/6
We move all terms to the left:
(2/3)t-(-1/6)=0
Domain of the equation: 3)t!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
(+2/3)t-(-1/6)=0
We multiply parentheses
2t^2-(-1/6)=0
We get rid of parentheses
2t^2+1/6=0
We multiply all the terms by the denominator
2t^2*6+1=0
Wy multiply elements
12t^2+1=0
a = 12; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·12·1
Δ = -48
Delta is less than zero, so there is no solution for the equation
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