(2/3)t-11=4(16-t)-(1/3)t

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Solution for (2/3)t-11=4(16-t)-(1/3)t equation:



(2/3)t-11=4(16-t)-(1/3)t
We move all terms to the left:
(2/3)t-11-(4(16-t)-(1/3)t)=0
Domain of the equation: 3)t!=0
t!=0/1
t!=0
t∈R
Domain of the equation: 3)t)!=0
t!=0/1
t!=0
t∈R
We add all the numbers together, and all the variables
(+2/3)t-(4(-1t+16)-(+1/3)t)-11=0
We multiply parentheses
2t^2-(4(-1t+16)-(+1/3)t)-11=0
We multiply all the terms by the denominator
2t^2*3)t)-(4(-1t-11*3)t)+1+16)-(=0
We add all the numbers together, and all the variables
2t^2*3)t)-(4(-1t-33)t)+1+16)-(=0
Wy multiply elements
6t^3-1t-33)t)+1+16)-(=0
We do not support etpression: t^3

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