(2/3)n=4n-(10/3)n-1/2

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Solution for (2/3)n=4n-(10/3)n-1/2 equation: 


n in (-oo:+oo)

(2/3)*n = 4*n-((10/3)*n)-(1/2) // - 4*n-((10/3)*n)-(1/2)

(2/3)*n-(4*n)+(10/3)*n+1/2 = 0

(2/3)*n-4*n+(10/3)*n+1/2 = 0

1/2 = 0

n belongs to the empty set

n belongs to the empty set

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