(2/3)ln(27)+ln(10)-(3ln(6))=ln(x)

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Solution for (2/3)ln(27)+ln(10)-(3ln(6))=ln(x) equation: 


D( x )

x <= 0

x <= 0

x in (0:+oo)

(2/3)*ln(27)+ln(10)-(3*ln(6)) = ln(x) // - ln(x)

(2/3)*ln(27)-ln(x)+ln(10)-(3*ln(6)) = 0

(2/3)*ln(27)-ln(x)+ln(10)-3*ln(6) = 0

ln(10)-ln(x)-3*ln(6)+2/3*ln(27) = 0 // - ln(10)-3*ln(6)+2/3*ln(27)

-ln(x) = -(ln(10)-3*ln(6)+2/3*ln(27))

-ln(x) = -(ln(10)-3*ln(6)+2/3*ln(27)) // * -1

ln(x) = ln(e^(ln(10)-3*ln(6)+2/3*ln(27)))

x = e^(ln(10)-3*ln(6)+2/3*ln(27))

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