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(2/3)a-8=11
We move all terms to the left:
(2/3)a-8-(11)=0
Domain of the equation: 3)a!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
(+2/3)a-8-11=0
We add all the numbers together, and all the variables
(+2/3)a-19=0
We multiply parentheses
2a^2-19=0
a = 2; b = 0; c = -19;
Δ = b2-4ac
Δ = 02-4·2·(-19)
Δ = 152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{152}=\sqrt{4*38}=\sqrt{4}*\sqrt{38}=2\sqrt{38}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{38}}{2*2}=\frac{0-2\sqrt{38}}{4} =-\frac{2\sqrt{38}}{4} =-\frac{\sqrt{38}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{38}}{2*2}=\frac{0+2\sqrt{38}}{4} =\frac{2\sqrt{38}}{4} =\frac{\sqrt{38}}{2} $
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