(2/3)+(3k/4)=(7112)

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Solution for (2/3)+(3k/4)=(7112) equation:


(2/3)+(3k/4)=(7112)

We simplify the equation to the form, which is simple to understand 
(2/3)+(3k/4)=(7112)

Simplifying:
( + 0.666666666667)+(3k/4)=(7112)

Simplifying:
( + 0.666666666667)+( + 0.75k)=(7112)

Remove unnecessary parentheses
 + 0.666666666667+( + 0.75k)=(7112)

Remove unnecessary parentheses
 + 0.666666666667 + 0.75k=+(+7112+)

Remove unnecessary parentheses
 + 0.666666666667 + 0.75k=7112

We move all terms containing k to the left and all other terms to the right. 
 + 0.75k=+7112-0.666666666667

We simplify left and right side of the equation. 
 + 0.75k=+7111.33333333

We divide both sides of the equation by 0.75 to get k. 
k=9481.77777778

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