(2/3)*x-(1/2)=x+(7/6)

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Solution for (2/3)*x-(1/2)=x+(7/6) equation: 



(2/3)*x-(1/2)=x+(7/6)

We move all terms to the left:

(2/3)*x-(1/2)-(x+(7/6))=0



Domain of the equation: 3)*x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)*x-(x+(+7/6))-(+1/2)=0

We multiply parentheses

2x^2-(x+(+7/6))-(+1/2)=0

We get rid of parentheses

2x^2-(x+(+7/6))-1/2=0

We calculate fractions


2x^2+(-(x+(+7*2)/()+()/()=0



We calculate terms in parentheses: +(-(x+(+7*2)/()+()/(), so:

-(x+(+7*2)/()+()/(

We can not solve this equation

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