(2/3)*(6*x-12)=(3/4)(8+12*x)

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Solution for (2/3)*(6*x-12)=(3/4)(8+12*x) equation: 



(2/3)(6x-12)=(3/4)(8+12x)

We move all terms to the left:

(2/3)(6x-12)-((3/4)(8+12x))=0



Domain of the equation: 3)(6x-12)!=0

x∈R





Domain of the equation: 4)(8+12x))!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(6x-12)-((+3/4)(12x+8))=0

We multiply parentheses ..

(+12x^2+2/3*-12)-((+3/4)(12x+8))=0

We calculate fractions


((+12x^2+2*4)(12x+8)))/(-12)*4)(12x+8))+3*)+()/(-12)*4)(12x+8))+3*)=0

We calculate fractions


(((+12x^2+2*4)(12x+8)))*(-12)*4)(12x+8))+3*))/((*(-12)*4)12x)+(-12)*4)(12x+8))+3*)+()*()/((*(-12)*4)12x)=0

We can not solve this equation

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