(2/3)(x-6)+1=5

Solution for (2/3)(x-6)+1=5 equation:

(2/3)(x-6)+1=5

We move all terms to the left:

(2/3)(x-6)+1-(5)=0


Domain of the equation: 3)(x-6)!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)(x-6)+1-5=0

We add all the numbers together, and all the variables

(+2/3)(x-6)-4=0

We multiply parentheses ..

(+2x^2+2/3*-6)-4=0

We multiply all the terms by the denominator


(+2x^2+2-4*3*-6)=0

We get rid of parentheses

2x^2+2-6-4*3*=0

We add all the numbers together, and all the variables

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$