(2/3)(x-5)=1+(3/4)(2-3x)

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Solution for (2/3)(x-5)=1+(3/4)(2-3x) equation: 



(2/3)(x-5)=1+(3/4)(2-3x)

We move all terms to the left:

(2/3)(x-5)-(1+(3/4)(2-3x))=0



Domain of the equation: 3)(x-5)!=0

x∈R





Domain of the equation: 4)(2-3x))!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(x-5)-(1+(+3/4)(-3x+2))=0

We multiply parentheses ..

(+2x^2+2/3*-5)-(1+(+3/4)(-3x+2))=0

We calculate fractions


((+2x^2+2*4)(-3x+2)))/(-5)*4)(-3x+2))+3*)+()/(-5)*4)(-3x+2))+3*)=0

We calculate fractions


(((+2x^2+2*4)(-3x+2)))*(-5)*4)(-3x+2))+3*))/(-3x)+(-5)*4)(-3x+2))+3*)+()*()/(-3x)=0

We can not solve this equation

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