(2/3)(c-3)=12

Solution for (2/3)(c-3)=12 equation:

(2/3)(c-3)=12

We move all terms to the left:

(2/3)(c-3)-(12)=0


Domain of the equation: 3)(c-3)!=0

c∈R


We add all the numbers together, and all the variables

(+2/3)(c-3)-12=0

We multiply parentheses ..

(+2c^2+2/3*-3)-12=0

We multiply all the terms by the denominator


(+2c^2+2-12*3*-3)=0

We get rid of parentheses

2c^2+2-3-12*3*=0

We add all the numbers together, and all the variables

2c^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{4}=0$