(2/3)(b+3)=(1/2)b+1

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Solution for (2/3)(b+3)=(1/2)b+1 equation: 



(2/3)(b+3)=(1/2)b+1

We move all terms to the left:

(2/3)(b+3)-((1/2)b+1)=0



Domain of the equation: 3)(b+3)!=0

b∈R





Domain of the equation: 2)b+1)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+2/3)(b+3)-((+1/2)b+1)=0

We multiply parentheses ..

(+2b^2+2/3*3)-((+1/2)b+1)=0

We calculate fractions

We do not support ebpression: b^3

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