(2/3)(6x+12)=-24

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Solution for (2/3)(6x+12)=-24 equation:



(2/3)(6x+12)=-24
We move all terms to the left:
(2/3)(6x+12)-(-24)=0
Domain of the equation: 3)(6x+12)!=0
x∈R
We add all the numbers together, and all the variables
(+2/3)(6x+12)-(-24)=0
We add all the numbers together, and all the variables
(+2/3)(6x+12)+24=0
We multiply parentheses ..
(+12x^2+2/3*12)+24=0
We multiply all the terms by the denominator
(+12x^2+2+24*3*12)=0
We get rid of parentheses
12x^2+2+24*3*12=0
We add all the numbers together, and all the variables
12x^2+866=0
a = 12; b = 0; c = +866;
Δ = b2-4ac
Δ = 02-4·12·866
Δ = -41568
Delta is less than zero, so there is no solution for the equation

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