(2/3)(3q+6=8

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Solution for (2/3)(3q+6=8 equation: 



(2/3)(3q+6=8

We move all terms to the left:

(2/3)(3q+6-(8)=0



Domain of the equation: 3)(3q+6-8!=0

We move all terms containing q to the left, all other terms to the right

3)(3q!=2

q∈R



We add all the numbers together, and all the variables

(+2/3)(3q+6-8=0

We multiply all the terms by the denominator


(+2=0

We add all the numbers together, and all the variables

=0

q=0/1

q=0

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