(2/3)(12-3x)=10

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Solution for (2/3)(12-3x)=10 equation: 



(2/3)(12-3x)=10

We move all terms to the left:

(2/3)(12-3x)-(10)=0



Domain of the equation: 3)(12-3x)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)(-3x+12)-10=0

We multiply parentheses ..

(-6x^2+2/3*12)-10=0

We multiply all the terms by the denominator


(-6x^2+2-10*3*12)=0

We get rid of parentheses

-6x^2+2-10*3*12=0

We add all the numbers together, and all the variables

-6x^2-358=0

a = -6; b = 0; c = -358;
Δ = b2-4ac
Δ = 02-4·(-6)·(-358)
Δ = -8592
Delta is less than zero, so there is no solution for the equation

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