(2.5x-3)+(2.5x-3)+(2.5x-3)+(2.5x-3)=(2x-2)+(2x-2)+(2x-2)

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Solution for (2.5x-3)+(2.5x-3)+(2.5x-3)+(2.5x-3)=(2x-2)+(2x-2)+(2x-2) equation: 



(2.5x-3)+(2.5x-3)+(2.5x-3)+(2.5x-3)=(2x-2)+(2x-2)+(2x-2)

We move all terms to the left:

(2.5x-3)+(2.5x-3)+(2.5x-3)+(2.5x-3)-((2x-2)+(2x-2)+(2x-2))=0

We get rid of parentheses

2.5x+2.5x+2.5x+2.5x-((2x-2)+(2x-2)+(2x-2))-3-3-3-3=0



We calculate terms in parentheses: -((2x-2)+(2x-2)+(2x-2)), so:

(2x-2)+(2x-2)+(2x-2)

We get rid of parentheses

2x+2x+2x-2-2-2

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

10x-(6x-6)-12=0

We get rid of parentheses

10x-6x+6-12=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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