(2-y)(2y-1)=0

Solution for (2-y)(2y-1)=0 equation:

Simplifying
(2 + -1y)(2y + -1) = 0

Reorder the terms:
(2 + -1y)(-1 + 2y) = 0

Multiply (2 + -1y) * (-1 + 2y)
(2(-1 + 2y) + -1y * (-1 + 2y)) = 0
((-1 * 2 + 2y * 2) + -1y * (-1 + 2y)) = 0
((-2 + 4y) + -1y * (-1 + 2y)) = 0
(-2 + 4y + (-1 * -1y + 2y * -1y)) = 0
(-2 + 4y + (1y + -2y2)) = 0

Combine like terms: 4y + 1y = 5y
(-2 + 5y + -2y2) = 0

Solving
-2 + 5y + -2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-2 + y)(1 + -2y) = 0

Subproblem 1
Set the factor '(-2 + y)' equal to zero and attempt to solve:

Simplifying
-2 + y = 0

Solving
-2 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + y = 0 + 2

Combine like terms: -2 + 2 = 0
0 + y = 0 + 2
y = 0 + 2

Combine like terms: 0 + 2 = 2
y = 2

Simplifying
y = 2
Subproblem 2
Set the factor '(1 + -2y)' equal to zero and attempt to solve:

Simplifying
1 + -2y = 0

Solving
1 + -2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2y = 0 + -1
-2y = 0 + -1

Combine like terms: 0 + -1 = -1
-2y = -1

Divide each side by '-2'.
y = 0.5

Simplifying
y = 0.5
Solution
y = {2, 0.5}