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(2-x)/2+2=5/2x
We move all terms to the left:
(2-x)/2+2-(5/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(-1x+2)/2-(+5/2x)+2=0
We get rid of parentheses
(-1x+2)/2-5/2x+2=0
We calculate fractions
2!=0
There is no solution for this equation
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