(2-x)+(x-4)*3=(3x+5)*2

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Solution for (2-x)+(x-4)*3=(3x+5)*2 equation: 



(2-x)+(x-4)*3=(3x+5)*2

We move all terms to the left:

(2-x)+(x-4)*3-((3x+5)*2)=0

We add all the numbers together, and all the variables

(-1x+2)+(x-4)*3-((3x+5)*2)=0

We multiply parentheses

(-1x+2)+3x-((3x+5)*2)-12=0

We get rid of parentheses

-1x+3x-((3x+5)*2)+2-12=0



We calculate terms in parentheses: -((3x+5)*2), so:

(3x+5)*2

We multiply parentheses

6x+10

Back to the equation:

-(6x+10)



We add all the numbers together, and all the variables

2x-(6x+10)-10=0

We get rid of parentheses

2x-6x-10-10=0

We add all the numbers together, and all the variables

-4x-20=0

We move all terms containing x to the left, all other terms to the right

-4x=20

x=20/-4

x=-5

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