(2-x)(3+x)=-15-4x-4x-x2

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Solution for (2-x)(3+x)=-15-4x-4x-x2 equation: 



(2-x)(3+x)=-15-4x-4x-x2

We move all terms to the left:

(2-x)(3+x)-(-15-4x-4x-x2)=0

We add all the numbers together, and all the variables

-(-8x-1x^2-15)+(-1x+2)(x+3)=0

We get rid of parentheses

1x^2+8x+(-1x+2)(x+3)+15=0

We multiply parentheses ..

1x^2+(-1x^2-3x+2x+6)+8x+15=0

We add all the numbers together, and all the variables

x^2+(-1x^2-3x+2x+6)+8x+15=0

We get rid of parentheses

x^2-1x^2-3x+2x+8x+6+15=0

We add all the numbers together, and all the variables

7x+21=0

We move all terms containing x to the left, all other terms to the right

7x=-21

x=-21/7

x=-3

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