(2-u)(2u-7)=0

Solution for (2-u)(2u-7)=0 equation:

(2-u)(2u-7)=0

We add all the numbers together, and all the variables

(-1u+2)(2u-7)=0

We multiply parentheses ..

(-2u^2+7u+4u-14)=0

We get rid of parentheses

-2u^2+7u+4u-14=0

We add all the numbers together, and all the variables

-2u^2+11u-14=0

a = -2; b = 11; c = -14;
Δ = b2-4ac
Δ = 112-4·(-2)·(-14)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3}{2*-2}=\frac{-14}{-4}
=3+1/2
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3}{2*-2}=\frac{-8}{-4}
=+2
$