(2-q/3)=6

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Solution for (2-q/3)=6 equation: 



(2-q/3)=6

We move all terms to the left:

(2-q/3)-(6)=0

We add all the numbers together, and all the variables

(-q/3+2)-6=0

We get rid of parentheses

-q/3+2-6=0

We multiply all the terms by the denominator


-q+2*3-6*3=0

We add all the numbers together, and all the variables

-1q-12=0

We move all terms containing q to the left, all other terms to the right

-q=12

q=12/-1

q=-12

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