(2-q)(q-4)=18

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Solution for (2-q)(q-4)=18 equation: 



(2-q)(q-4)=18

We move all terms to the left:

(2-q)(q-4)-(18)=0

We add all the numbers together, and all the variables

(-1q+2)(q-4)-18=0

We multiply parentheses ..

(-1q^2+4q+2q-8)-18=0

We get rid of parentheses

-1q^2+4q+2q-8-18=0

We add all the numbers together, and all the variables

-1q^2+6q-26=0

a = -1; b = 6; c = -26;
Δ = b2-4ac
Δ = 62-4·(-1)·(-26)
Δ = -68
Delta is less than zero, so there is no solution for the equation

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