(2-n))/(n+1)+(2n-4)/(2-n)=1

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Solution for (2-n))/(n+1)+(2n-4)/(2-n)=1 equation: 



(2-n))/(n+1)+(2n-4)/(2-n)=1

We move all terms to the left:

(2-n))/(n+1)+(2n-4)/(2-n)-(1)=0



Domain of the equation: (n!=0

n∈R



We add all the numbers together, and all the variables

(-1n+2))/(n+n)-1-4)/(2+1)+(=0

We calculate fractions


((-1n+2))*3+()/((n*3+()+n-1-4)*n/((n*3+()=0



We calculate terms in parentheses: +()/((n*3+()+n-1-4)*n/((n*3+(), so:

)/((n*3+()+n-1-4)*n/((n*3+(

We can not solve this equation

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