(2-j)(3+j)(20-10j)=0

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Solution for (2-j)(3+j)(20-10j)=0 equation:



(2-j)(3+j)(20-10j)=0
We add all the numbers together, and all the variables
(-1j+2)(j+3)(-10j+20)=0
We multiply parentheses ..
(-1j^2-3j+2j+6)(-10j+20)=0

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