(2-i)(4+i)=

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Solution for (2-i)(4+i)= equation:


Simplifying
(2 + -1i)(4 + i) = 0

Multiply (2 + -1i) * (4 + i)
(2(4 + i) + -1i * (4 + i)) = 0
((4 * 2 + i * 2) + -1i * (4 + i)) = 0
((8 + 2i) + -1i * (4 + i)) = 0
(8 + 2i + (4 * -1i + i * -1i)) = 0
(8 + 2i + (-4i + -1i2)) = 0

Combine like terms: 2i + -4i = -2i
(8 + -2i + -1i2) = 0

Solving
8 + -2i + -1i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(2 + -1i)(4 + i) = 0

Subproblem 1

Set the factor '(2 + -1i)' equal to zero and attempt to solve: Simplifying 2 + -1i = 0 Solving 2 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1i = 0 + -2 -1i = 0 + -2 Combine like terms: 0 + -2 = -2 -1i = -2 Divide each side by '-1'. i = 2 Simplifying i = 2

Subproblem 2

Set the factor '(4 + i)' equal to zero and attempt to solve: Simplifying 4 + i = 0 Solving 4 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + i = 0 + -4 Combine like terms: 4 + -4 = 0 0 + i = 0 + -4 i = 0 + -4 Combine like terms: 0 + -4 = -4 i = -4 Simplifying i = -4

Solution

i = {2, -4}

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