(2-i)(3+2i)=

Solution for (2-i)(3+2i)= equation:

Simplifying
(2 + -1i)(3 + 2i) = 0

Multiply (2 + -1i) * (3 + 2i)
(2(3 + 2i) + -1i * (3 + 2i)) = 0
((3 * 2 + 2i * 2) + -1i * (3 + 2i)) = 0
((6 + 4i) + -1i * (3 + 2i)) = 0
(6 + 4i + (3 * -1i + 2i * -1i)) = 0
(6 + 4i + (-3i + -2i2)) = 0

Combine like terms: 4i + -3i = 1i
(6 + 1i + -2i2) = 0

Solving
6 + 1i + -2i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(2 + -1i)(3 + 2i) = 0

Subproblem 1
Set the factor '(2 + -1i)' equal to zero and attempt to solve:

Simplifying
2 + -1i = 0

Solving
2 + -1i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1i = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1i = 0 + -2
-1i = 0 + -2

Combine like terms: 0 + -2 = -2
-1i = -2

Divide each side by '-1'.
i = 2

Simplifying
i = 2
Subproblem 2
Set the factor '(3 + 2i)' equal to zero and attempt to solve:

Simplifying
3 + 2i = 0

Solving
3 + 2i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2i = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2i = 0 + -3
2i = 0 + -3

Combine like terms: 0 + -3 = -3
2i = -3

Divide each side by '2'.
i = -1.5

Simplifying
i = -1.5
Solution
i = {2, -1.5}