(2-9z)/(17-4z)=4/5

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Solution for (2-9z)/(17-4z)=4/5 equation: 



(2-9z)/(17-4z)=4/5

We move all terms to the left:

(2-9z)/(17-4z)-(4/5)=0



Domain of the equation: (17-4z)!=0

We move all terms containing z to the left, all other terms to the right

-4z!=-17

z!=-17/-4

z!=4+1/4

z∈R



We add all the numbers together, and all the variables

(-9z+2)/(-4z+17)-(+4/5)=0

We get rid of parentheses

(-9z+2)/(-4z+17)-4/5=0

We calculate fractions


(-45z+10)/(-20z+85)+(16z-68)/(-20z+85)=0

We multiply all the terms by the denominator


(-45z+10)+(16z-68)=0

We get rid of parentheses

-45z+16z+10-68=0

We add all the numbers together, and all the variables

-29z-58=0

We move all terms containing z to the left, all other terms to the right

-29z=58

z=58/-29

z=-2

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