(2-6y)/3=(2-y-2y)/2

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Solution for (2-6y)/3=(2-y-2y)/2 equation: 



(2-6y)/3=(2-y-2y)/2

We move all terms to the left:

(2-6y)/3-((2-y-2y)/2)=0

We add all the numbers together, and all the variables

(-6y+2)/3-((-3y+2)/2)=0

We calculate fractions


(-6y)/()+(-((-3y+2)*3)/()=0



We calculate terms in parentheses: +(-((-3y+2)*3)/(), so:

-((-3y+2)*3)/(

We multiply all the terms by the denominator


-((-3y+2)*3)



We calculate terms in parentheses: -((-3y+2)*3), so:

(-3y+2)*3

We multiply parentheses

-9y+6

Back to the equation:

-(-9y+6)



We get rid of parentheses

9y-6

Back to the equation:

+(9y-6)



We get rid of parentheses

(-6y)/()+9y-6=0

We multiply all the terms by the denominator


(-6y)+9y*()-6*()=0

We add all the numbers together, and all the variables

(-6y)+9y*()=0

We get rid of parentheses

-6y+9y*()=0

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