(2-5z+i)(2iz+1)=0

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Solution for (2-5z+i)(2iz+1)=0 equation:


Simplifying
(2 + -5z + i)(2iz + 1) = 0

Reorder the terms:
(2 + i + -5z)(2iz + 1) = 0

Reorder the terms:
(2 + i + -5z)(1 + 2iz) = 0

Multiply (2 + i + -5z) * (1 + 2iz)
(2(1 + 2iz) + i(1 + 2iz) + -5z * (1 + 2iz)) = 0
((1 * 2 + 2iz * 2) + i(1 + 2iz) + -5z * (1 + 2iz)) = 0
((2 + 4iz) + i(1 + 2iz) + -5z * (1 + 2iz)) = 0
(2 + 4iz + (1 * i + 2iz * i) + -5z * (1 + 2iz)) = 0
(2 + 4iz + (1i + 2i2z) + -5z * (1 + 2iz)) = 0
(2 + 4iz + 1i + 2i2z + (1 * -5z + 2iz * -5z)) = 0

Reorder the terms:
(2 + 4iz + 1i + 2i2z + (-10iz2 + -5z)) = 0
(2 + 4iz + 1i + 2i2z + (-10iz2 + -5z)) = 0

Reorder the terms:
(2 + 1i + 4iz + -10iz2 + 2i2z + -5z) = 0
(2 + 1i + 4iz + -10iz2 + 2i2z + -5z) = 0

Solving
2 + 1i + 4iz + -10iz2 + 2i2z + -5z = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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