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Simplifying (2 + -5i)(2 + 5i) * i = 29 Reorder the terms for easier multiplication: i(2 + -5i)(2 + 5i) = 29 Multiply (2 + -5i) * (2 + 5i) i(2(2 + 5i) + -5i * (2 + 5i)) = 29 i((2 * 2 + 5i * 2) + -5i * (2 + 5i)) = 29 i((4 + 10i) + -5i * (2 + 5i)) = 29 i(4 + 10i + (2 * -5i + 5i * -5i)) = 29 i(4 + 10i + (-10i + -25i2)) = 29 Combine like terms: 10i + -10i = 0 i(4 + 0 + -25i2) = 29 i(4 + -25i2) = 29 (4 * i + -25i2 * i) = 29 (4i + -25i3) = 29 Solving 4i + -25i3 = 29 Solving for variable 'i'. Reorder the terms: -29 + 4i + -25i3 = 29 + -29 Combine like terms: 29 + -29 = 0 -29 + 4i + -25i3 = 0 The solution to this equation could not be determined.
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