(2-3x)(3+5x)=0

Solution for (2-3x)(3+5x)=0 equation:

(2-3x)(3+5x)=0

We add all the numbers together, and all the variables

(-3x+2)(5x+3)=0

We multiply parentheses ..

(-15x^2-9x+10x+6)=0

We get rid of parentheses

-15x^2-9x+10x+6=0

We add all the numbers together, and all the variables

-15x^2+x+6=0

a = -15; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-15)·6
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-19}{2*-15}=\frac{-20}{-30}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+19}{2*-15}=\frac{18}{-30}
=-3/5
$