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(2-3i)=(-6+8i)
We move all terms to the left:
(2-3i)-((-6+8i))=0
We add all the numbers together, and all the variables
(-3i+2)-((8i-6))=0
We get rid of parentheses
-3i-((8i-6))+2=0
We calculate terms in parentheses: -((8i-6)), so:We get rid of parentheses
(8i-6)
We get rid of parentheses
8i-6
Back to the equation:
-(8i-6)
-3i-8i+6+2=0
We add all the numbers together, and all the variables
-11i+8=0
We move all terms containing i to the left, all other terms to the right
-11i=-8
i=-8/-11
i=8/11
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