(2+x)(x-7)/(x-5)(x+4)=1

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Solution for (2+x)(x-7)/(x-5)(x+4)=1 equation: 



(2+x)(x-7)/(x-5)(x+4)=1

We move all terms to the left:

(2+x)(x-7)/(x-5)(x+4)-(1)=0



Domain of the equation: (x-5)(x+4)!=0

We move all terms containing x to the left, all other terms to the right

x-5)(x!=-4

x∈R



We add all the numbers together, and all the variables

(x+2)(x-7)/(x-5)(x+4)-1=0

We multiply parentheses ..

(+x^2-7x+2x-14)/(x-5)(x+4)-1=0

We multiply all the terms by the denominator


(+x^2-7x+2x-14)-1*(x-5)(x+4)=0

We get rid of parentheses

x^2-7x+2x-1*(x-5)(x+4)-14=0

We multiply parentheses ..

x^2-1*(+x^2+4x-5x-20)-7x+2x-14=0

We add all the numbers together, and all the variables

x^2-1*(+x^2+4x-5x-20)-5x-14=0

We move all terms containing x to the left, all other terms to the right

x^2-1*(+x^2+4x-5x-20)-5x=14

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