(2+x)(x-5)=56

Solution for (2+x)(x-5)=56 equation:

(2+x)(x-5)=56

We move all terms to the left:

(2+x)(x-5)-(56)=0

We add all the numbers together, and all the variables

(x+2)(x-5)-56=0

We multiply parentheses ..

(+x^2-5x+2x-10)-56=0

We get rid of parentheses

x^2-5x+2x-10-56=0

We add all the numbers together, and all the variables

x^2-3x-66=0

a = 1; b = -3; c = -66;
Δ = b2-4ac
Δ = -32-4·1·(-66)
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{273}}{2*1}=\frac{3-\sqrt{273}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{273}}{2*1}=\frac{3+\sqrt{273}}{2}
$